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[simantics/platform.git] / bundles / org.simantics.charts / src / org / simantics / charts / query / NextChartItemIndexQuery.java
1 /*******************************************************************************\r
2  * Copyright (c) 2007, 2011 Association for Decentralized Information Management in\r
3  * Industry THTH ry.\r
4  * All rights reserved. This program and the accompanying materials\r
5  * are made available under the terms of the Eclipse Public License v1.0\r
6  * which accompanies this distribution, and is available at\r
7  * http://www.eclipse.org/legal/epl-v10.html\r
8  *\r
9  * Contributors:\r
10  *     VTT Technical Research Centre of Finland - initial API and implementation\r
11  *******************************************************************************/\r
12 package org.simantics.charts.query;\r
13 \r
14 import org.simantics.charts.ontology.ChartResource;\r
15 import org.simantics.db.ReadGraph;\r
16 import org.simantics.db.Resource;\r
17 import org.simantics.db.common.request.Queries;\r
18 import org.simantics.db.common.request.ResourceRead;\r
19 import org.simantics.db.exception.DatabaseException;\r
20 import org.simantics.layer0.Layer0;\r
21 \r
22 /**\r
23  * Query to chart for next available item index.\r
24  * This is the largest item index found + 1.\r
25  * \r
26  * @author toni.kalajainen\r
27  */\r
28 public class NextChartItemIndexQuery extends ResourceRead<Integer> {\r
29 \r
30         public NextChartItemIndexQuery(Resource resource) {\r
31                 super(resource);\r
32         }\r
33 \r
34         @Override\r
35         public Integer perform(ReadGraph graph) throws DatabaseException {\r
36         Layer0 L0 = Layer0.getInstance(graph);\r
37         ChartResource CHART = ChartResource.getInstance(graph);\r
38                 \r
39         int largest = 0;\r
40         for (Resource item : graph.syncRequest(Queries.objectsWithType(resource, L0.ConsistsOf, CHART.Chart_Item))) {\r
41                 Integer index = graph.getPossibleRelatedValue(item, CHART.Chart_Item_Index);\r
42                 if (index != null) largest = Math.max(largest, index);\r
43         }\r
44         \r
45                 return largest+1;\r
46         }\r
47 \r
48 }\r